Sheetal Sahu Crowned Miss India Odisha 2019

Kolkata: Odia girl Sheetal Sahu was crowned Femina Miss India Odisha 2019 in a glitzy ceremony in Kolkata last night.

Finalists of 13 East zone states, namely Odisha, Chhattisgarh, Bihar, Jharkhand, Sikkim, Assam, Mizoram, Tripura, Nagaland, Meghalaya, Arunachal Pradesh, Manipur and West Bengal, participated the coveted crown and represented their states in the most prestigious beauty pageant of the country, Femina Miss India 2019.

A software engineer by profession, Sheetal Sahu was born in Rayagada district and was working in Mumbai before participating in the Miss India contest.

Her big test will come on June 15 when she stakes her claim for the crown in the grand finale going to be held in Mumbai. The finalists of FBB Colors Femina Miss India 2019 will undergo rigorous training and grooming sessions from experts of the industry.



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